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electrical_engineering_and_electronics_2:task_5.2.6 [2025/09/19 16:00] – gelöscht - Externe Bearbeitung (Unbekanntes Datum) 127.0.0.1electrical_engineering_and_electronics_2:task_5.2.6 [2025/09/19 16:00] (aktuell) – ↷ Seitename wurde von electrical_engineering_and_electronics_2:task_1.1.4 auf electrical_engineering_and_electronics_2:task_5.2.6 geändert mexleadmin
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 +<panel type="info" title="Task 5.2.6 Variation: Forces on Charges (exam task, ca 8% of a 60 minute exam, WS2020)"> <WRAP group><WRAP column 2%>{{fa>pencil?32}}</WRAP><WRAP column 92%>
  
 +<WRAP right>
 +{{drawio>electrical_engineering_2:coulombkraftgeometrieii.svg}}
 +</WRAP>
 +
 +Given is an arrangement of electric charges located in a vacuum (see picture on the right). \\
 +The charges have the following values:  \\
 +$Q_1=5   ~\rm{µC}$ (point charge) \\
 +$Q_2=-10 ~\rm{µC}$ (point charge) \\
 +$Q_3= 0  ~\rm{C}$ (infinitely extended surface charge)
 +
 +$\varepsilon_0=8.854\cdot 10^{-12}  ~\rm{F/m}$  , $\varepsilon_r=1$
 +
 +1. calculate the magnitude of the force of $Q_2$ on $Q_1$, without the force effect of $Q_3$.
 +
 +<button size="xs" type="link" collapse="Loesung_5_1_4_1_Endergebnis">{{icon>eye}} Result</button><collapse id="Loesung_5_1_4_1_Endergebnis" collapsed="true">
 +\begin{align*}
 + |\vec{F}_C| = 1.321 ~\rm{N} \rightarrow 1.3 ~\rm{N}
 +\end{align*}
 + \\
 +</collapse>
 +
 +2. is this force attractive or repulsive?
 +
 +<button size="xs" type="link" collapse="Loesung_5_1_4_2_Endergebnis">{{icon>eye}} Solution </button><collapse id="Loesung_5_1_4_2_Endergebnis" collapsed="true">
 +The force is repulsive because both charges have the same sign. \\ \\ \\
 +</collapse>
 +
 +Now let $Q_2=0$ and the surface charge $Q_3$ be designed in such a way that a homogeneous electric field with $E_3=500 ~\rm{kV/m}$ results. \\ 
 +What force (magnitude) now results on $Q_1$?
 +
 +<button size="xs" type="link" collapse="Loesung_5_1_4_3_Endergebnis">{{icon>eye}} Result</button><collapse id="Loesung_5_1_4_3_Endergebnis" collapsed="true">
 +\begin{align*}
 + |\vec{F}_C| = 2.5 ~\rm{N}
 +\end{align*} \\
 +</collapse>
 +
 +
 +</WRAP></WRAP></panel>